Maharashtra Board Textbook Solutions for Standard Eight

Chapter 9 - Map Scale

(1) (a) Classify maps showing the following areas into small scale or large scale

(1) Building 

(2) School

(3) Country of India 

(4) Church

(5) Mall 

(6) World Map

(7) Garden 

(8) Dispensary 

(9) Maharashtra State 

(10) The north sky at night

Ans: The classification of maps showing the given areas is as follows:

(A) Small scale maps:

Country of India

World map

Maharashtra state

The north sky at night

 

(B) Large scale maps:

Building

School

Church

Mall

Garden

Dispensary

 

(b) There are two maps with respective scales of 1cm = 100m and 1cm = 100km. 

Give a well reasoned answer as to which of them would be a large scale map and which a small scale map. Recognize the type of maps. 

Ans: 

Cities Distance on map Actual Distance
Mumbai to Bengaluru
………….
…………. km
Vijaypura to Jaipur
………….
…………. km
Hyderabad to Surat
………….
…………. km
Ujjain to Shimla
………….
…………. km
Patna to Raipur
………….
…………. km
Delhi to Kolkata
………….
…………. km

Ans: Using a map with a numerical scale of 1:18,000,000, the following are the distances:

Cities Distance on map Actual Distance
Mumbai to Bengaluru
0.98 cm
980 km
Vijaypura to Jaipur
2 cm
2000 km
Hyderabad to Surat
0.9 cm
900 km
Ujjain to Shimla
1.14 cm
1140 km
Patna to Raipur
0.75 cm
750 km
Delhi to Kolkata
1 cm
1000 km

(3) (a) The distance between two points A and B on the Ground is 500 m. Show this distance on paper by a line of 2 cm. Express the map scale by any one method and mention it.

Ans: To calculate the scale, we need to convert the 500 m into cm

500 m = 50,000 cm

 

2 cm on paper = 50,000 cm on ground

∴ 1 cm on paper = 25,000 cm on ground

 

On a verbal scale, this can be expressed as 1 cm = 25,000 cm, or 1 cm = 250 m. This is called verbal scale because it is written in the form of words and units. 

 

(b) Convert verbal scale of 1cm = 53 km to a numerical scale

Ans: 

(i) 1 kilometre is equal to 100000 centimetres. Therefore, 53 kilometres is equal to 5300000 centimetres.

(ii) Therefore, the verbal scale of 1 cm = 53 km can be converted to a numerical scale as – 1 : 5300000.

 

(c) Convert the numerical scale of 1:10,000 000 to a verbal scale in the metric system.

Ans:

(i) 100000 centimetres is equal to 1 kilometre. Thus, 10000000 centimetres is equal to 100 kilometres.

(ii) Therefore, numerical scale of 1 : 10000000 to a verbal scale in the metric system can be converted as 1 cm = 100 km.

Q (4) Help them, using road and railway maps of the state of Maharashtra. Use the scale given in the maps.

(a) Ajay wants to arrange a family trip. Beed-Aurangabad-Dhule-Nasik-Mumbai-Pune-Solapur-Beed. He wants to visit tourist places along this route. The cost of the vehicle is Rs 12/- per km. What would be the approximate cost of travel?

Ans: 

(i) To calculate the approximate travel cost, we need to know the distance that person A has planned to travel.

(iii) Therefore, the total distance travelled by person A is 1,207 km. The approximate cost of travel would be 1207 × 12 = ₹14,484. 

 

(b) Saloni has been asked to organize a trip by her teacher. She has selected Nagpur-Chandrapur-Nanded-Washim-Akola-Malkapur. What would be the total coverage in kilometers?

Ans: 

(i) To calculate the total coverage in terms of kilometres, we need to find the distance between the places and add them.

(iii) Therefore, the total coverage is 830 km. 

 

(c) Vishawasrao is transporting goods in a vehicle from Alibag (district – Raigad) to Naldurg (district – Osmanabad). How many km. will he be covering approximately for a to and fro travel?

Ans: 

(i) The distance between Alibag to Naldurg is 436.5km. 

(ii) Since person V would be travelling to and from these places, the distance would be 436.5 x 2 = 873 km. 

(iii) Therefore, the total distance covered by Person V is 873 km.